3y^2-15y-2250=0

Solution for 3y^2-15y-2250=0 equation:

3y^2-15y-2250=0

a = 3; b = -15; c = -2250;
Δ = b2-4ac
Δ = -152-4·3·(-2250)
Δ = 27225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{27225}=165$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-165}{2*3}=\frac{-150}{6}
=-25
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+165}{2*3}=\frac{180}{6}
=30
$